Program Execution of X<nn?

[Karpurk]

Hello, I'm working on a program where I need to use "X<nn?" where "nn" is the location of a previously stored number.

I have tried to key that line into my program using just the Alpha input method (pressing the ALPHA key and entering the string without pressing the XEQ key), and also the XEQ/Alpha input method. When my program gets to that line, the program halts and my HP-41 displays "NONEXISTANT". The issue seems to be the "nn" portion of the string. All non-"nn" conditional strings can be entered using the Alpha input method, and they work properly.

Thanks,
Larry Karpurk

[pcscote]

to enter or execute the function, do:

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[XEQ] [ALPHA] X<NN? [ALPHA]

Usage

Setup: put 20 in register 2

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20 [STO] 02

Display YES : compare 19 (in X) with the content of register 2 (indirect Y)

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2 [ENTER] 19 [XEQ] [ALPHA] X<NN? [ALPHA]

Display NO : compare 20 (in X) with the content of register 2 (indirect Y)

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2 [ENTER] 20 [XEQ] [ALPHA] X<NN? [ALPHA]

[Karpurk]

Thank you for your response.

With data already in "STO 20"; I put [XEQ] [ALPHA] X<20? [ALPHA] in the program.

When the program runs this line it stops and displays "NONEXISTANT"

I am assuming that the way I have entered the command, the computer compares the X register to what I have stored in "STO 20" location. Is that correct?

(Please let me know if you can get these entries to work on your HP-41).

Best regards,
Larry

[Garth]

I put [XEQ] [ALPHA] X<20? [ALPHA] in the program.

The "NN" is part of the instruction's literal name, not a number like with STO 20.  At run time, X<NN? will compare the contents of X to the contents of a register pointed to by Y.

[Karpurk]

Thanks guys,

It works!